Five percent test, 5 and 10 df
| A | B | C | |
|---|---|---|---|
| 1 | p | df1 | df2 |
| 2 | 0.05 | 5 | 10 |
Formula: E2: =ROUND(F.INV.RT(A2,B2,C2),4)
Result: 3.3258
A statistic above 3.3258 is significant at 5% with these degrees of freedom.
F.INV.RT with worked examples you can test in the live grid. The argument details are in the Excel guide.
The arguments and common errors are covered in the F.INV.RT Excel guide; check the function help in Google Sheets for its own argument list.
| A | B | C | |
|---|---|---|---|
| 1 | p | df1 | df2 |
| 2 | 0.05 | 5 | 10 |
Formula: E2: =ROUND(F.INV.RT(A2,B2,C2),4)
Result: 3.3258
A statistic above 3.3258 is significant at 5% with these degrees of freedom.
| A | B | C | |
|---|---|---|---|
| 1 | p | df1 | df2 |
| 2 | 0.05 | 2 | 2 |
Formula: E2: =ROUND(F.INV.RT(A2,B2,C2),4)
Result: 19
With two and two degrees of freedom the 5% cutoff is exactly 19.
| A | B | C | |
|---|---|---|---|
| 1 | p | df1 | df2 |
| 2 | 0.5 | 2 | 2 |
Formula: E2: =ROUND(F.INV.RT(A2,B2,C2),4)
Result: 1
With two and two degrees of freedom, the median cutoff is one.
A tiny spreadsheet with example data. Edit the formula or any number and see the result.
Formula in D2: =F.INV.RT(0.05,2,12)
| A | B | C | D | |
|---|---|---|---|---|
| 1 | Number | Step | Result | |
| 2 | 1234.567 | 50 | 3.88529383465 | |
| 3 | 17 | 5 | ||
| 4 | -4.7 | 12 | ||
| 5 | 144 | 9 | ||
| 6 | 2.5 | 3 | ||
| 7 | 50 | 12 |
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